user: implement mlibc as the libc, finally.
It's finally done.. Signed-off-by: kaguya <vpshinomiya@protonmail.com>
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@@ -0,0 +1,30 @@
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#include <regex.h>
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#include <stdio.h>
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#include <stdlib.h>
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#include <assert.h>
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int main(void) {
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char *testString = "mlibc is the best best best libc";
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char *pattern = "\\(be[a-z]t\\) \\1";
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regex_t reg;
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int rc = regcomp(®, pattern, 0);
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assert(!rc);
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regmatch_t matches[2];
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rc = regexec(®, testString, 2, matches, 0);
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assert(!rc);
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printf("Whole pattern: \"%.*s\" at %zd-%zd.\n",
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(int)(matches[0].rm_eo - matches[0].rm_so), &testString[matches[0].rm_so],
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(ssize_t)matches[0].rm_so, (ssize_t)(matches[0].rm_eo - 1));
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assert(matches[0].rm_so == 13 && matches[0].rm_eo == 22);
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printf("Substring: \"%.*s\" at %zd-%zd.\n",
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(int)(matches[1].rm_eo - matches[1].rm_so), &testString[matches[1].rm_so],
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(ssize_t)matches[1].rm_so, (ssize_t)matches[1].rm_eo - 1);
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assert(matches[1].rm_so == 13 && matches[1].rm_eo == 17);
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regfree(®);
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return 0;
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}
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